OUT:1{从当前柱算起，需要5天的历史数据}
AND REF(MAX(O,C),1) = LLV(MAX(O,C),3)
AND C>O
AND REF(C,2) < REF(O,2)
AND REF(ABS(C-O),2) > REF(ABS(C-O),1)*1.5{倒数，第二根的柱体很小}
AND REF(C,3) > REF(C,2)
AND REF(C,4) > REF(C,3)
;